117° Вправа 117Алгебра 8 клас Тарасенкова 2025 · § 3 · стор. 38

117. Зведіть дріб 1/(3b) до знаменника:

1) ${\displaystyle \frac{1^{\mathrm{\setminus }3}}{3b}=}$${\displaystyle \frac{1\cdot 3}{3b\cdot 3}=}$${\displaystyle \frac{3}{9b}}$;

2) ${\displaystyle \frac{1^{\mathrm{\setminus }6}}{3b}=}$${\displaystyle \frac{1\cdot 6}{3b\cdot 6}=}$${\displaystyle \frac{6}{18b}}$;

3) ${\displaystyle \frac{1^{\mathrm{\setminus }b}}{3b}=}$${\displaystyle \frac{1\cdot b}{3b\cdot b}=}$${\displaystyle \frac{b}{3b^2}}$;

4) ${\displaystyle \frac{1^{\mathrm{\setminus }2b}}{3b}=}$${\displaystyle \frac{1\cdot 2b}{3b\cdot 2b}=}$${\displaystyle \frac{2b}{6b^2}}$;

5) ${\displaystyle \frac{1^{\mathrm{\setminus }5b^2}}{3b}=}$${\displaystyle \frac{1\cdot 5b^2}{3b\cdot 5b^2}=}$${\displaystyle \frac{5b^2}{15b^3}}$;

6) ${\displaystyle \frac{1^{\mathrm{\setminus }7b^3}}{3b}=}$${\displaystyle \frac{1\cdot 7b^3}{3b\cdot 7b^3}=}$${\displaystyle \frac{7b^3}{21b^4}}$.