720° Вправа 720Алгебра 8 клас Тарасенкова 2025 · § 17 · стор. 214

720. Назвіть коефіцієнти квадратного рівняння:

1) ${\displaystyle 6x^2+5x-1=}$${\displaystyle 0}$: ${\displaystyle a=}$${\displaystyle 6}$, ${\displaystyle b=}$${\displaystyle 5}$, ${\displaystyle c=}$${\displaystyle -1}$;

2) ${\displaystyle x^2+x-6=}$${\displaystyle 0}$: ${\displaystyle a=}$${\displaystyle 1}$, ${\displaystyle b=}$${\displaystyle 1}$, ${\displaystyle c=}$${\displaystyle -6}$;

3) ${\displaystyle 2x^2-12=}$${\displaystyle 0}$: ${\displaystyle a=}$${\displaystyle 2}$, ${\displaystyle b=}$${\displaystyle 0}$, ${\displaystyle c=}$${\displaystyle -12}$;

4) ${\displaystyle x^2+2x=}$${\displaystyle 0}$: ${\displaystyle a=}$${\displaystyle 1}$, ${\displaystyle b=}$${\displaystyle 2}$, ${\displaystyle c=}$${\displaystyle 0}$;

5) ${\displaystyle 6x^2=}$${\displaystyle 0}$: ${\displaystyle a=}$${\displaystyle 6}$, ${\displaystyle b=}$${\displaystyle 0}$, ${\displaystyle c=}$${\displaystyle 0}$;

6) ${\displaystyle 5+x^2-6x=}$${\displaystyle 0}$;

${\displaystyle x^2-6x+5=}$${\displaystyle 0}$: ${\displaystyle a=}$${\displaystyle 1}$, ${\displaystyle b=}$${\displaystyle -6}$, ${\displaystyle c=}$${\displaystyle 5}$.

Зведеними є рівняння 2), 4) і 6), бо в них ${\displaystyle a=}$${\displaystyle 1}$.