441 Вправа 441Алгебра 8 клас Бевз 2025 · § 9 · стор. 90

441. Спрости вираз.

а) ${\displaystyle a^{-10}\cdot a^8=}$${\displaystyle a^{-10+8}=}$${\displaystyle a^{-2}}$;

б) ${\displaystyle x^5\cdot x^0=}$${\displaystyle x^{5+0}=}$${\displaystyle x^5}$;

в) ${\displaystyle c^{12}\cdot c^{-10}=}$${\displaystyle c^{12-10}=}$${\displaystyle c^2}$;

г) ${\displaystyle a^3:a^{-3}=}$${\displaystyle a^{3+3}=}$${\displaystyle a^6}$;

ґ) ${\displaystyle a^{-7}:a^{-5}=}$${\displaystyle a^{-7+5}=}$${\displaystyle a^{-2}}$;

д) ${\displaystyle a^{11}\cdot a^{-15}:a^3=}$${\displaystyle a^{11-15-3}=}$${\displaystyle a^{-7}}$;

е) ${\displaystyle p^{-6}\cdot {\left(p^{-2}\right)}^{-4}=}$${\displaystyle p^{-6}\cdot p^{\left(-2\right)\cdot \left(-4\right)}=}$${\displaystyle p^{-6}\cdot p^8}$=

=${\displaystyle p^{-6+8}=}$${\displaystyle p^2}$;

є) ${\displaystyle {\left(c^{-2}\right)}^5:{\left(c^3\right)}^{-8}\cdot a^{14}=}$${\displaystyle c^{-2\cdot 5}:c^{3\cdot \left(-8\right)}\cdot a^{14}}$=

=${\displaystyle c^{-10}:c^{-24}\cdot a^{14}=}$${\displaystyle c^{-10+24}\cdot a^{14}=}$${\displaystyle a^{14}{c}^{14}}$.