472 Вправа 472Алгебра 8 клас Бевз 2025 · § 9 · стор. 93

472. Розв’яжи рівняння.

а) ${\displaystyle x^{-1}-4x^{-3}=}$${\displaystyle 0}$;

${\displaystyle \frac{1}{x}-\frac{4}{x^3}=}$${\displaystyle 0}$;

${\displaystyle \frac{x^2-4}{x^3}=}$${\displaystyle 0}$;

${\displaystyle \{\begin{array}{rl}& (x-2)(x+2)=0,\\ & x\ne 0;\end{array}}$ ${\displaystyle x=}$${\displaystyle \pm 2}$;

б) ${\displaystyle x^{-1}+x=}$${\displaystyle 2}$;

${\displaystyle \frac{1}{x}+x=}$${\displaystyle 2}$;

${\displaystyle x\ne 0}$;

${\displaystyle 1+x^2=}$${\displaystyle 2x}$;

${\displaystyle {(x-1)}^2=}$${\displaystyle 0}$;

${\displaystyle x=}$${\displaystyle 1}$.