423 Вправа 423Алгебра 8 клас Бевз 2025 · § 9 · стор. 88

423. Обчисли.

а) за означенням ${\displaystyle a^0=}$${\displaystyle 1}$ (${\displaystyle a\ne 0}$):

${\displaystyle 35^0=}$${\displaystyle 1}$;

${\displaystyle {(-8)}^0=}$${\displaystyle 1}$;

${\displaystyle {\left(\frac{2}{3}\right)}^0=}$${\displaystyle 1}$;

${\displaystyle 1,23^0=}$${\displaystyle 1}$;

${\displaystyle {\left(4\frac{1}{3}\right)}^0=}$${\displaystyle 1}$;

б) за означенням ${\displaystyle a^{-1}=}$${\displaystyle \frac{1}{a}}$:

${\displaystyle 2^{-1}=}$${\displaystyle \frac{1}{2}}$;

${\displaystyle 6^{-1}=}$${\displaystyle \frac{1}{6}}$;

${\displaystyle {\left(\frac{1}{5}\right)}^{-1}=}$${\displaystyle 5}$;

${\displaystyle {\left(\frac{3}{7}\right)}^{-1}=}$${\displaystyle \frac{7}{3}}$;

${\displaystyle {(-5)}^{-1}=}$${\displaystyle -\frac{1}{5}}$;

${\displaystyle 0,3^{-1}=}$${\displaystyle {\left(\frac{3}{10}\right)}^{-1}=}$${\displaystyle \frac{10}{3}}$;

${\displaystyle 0,02^{-1}=}$${\displaystyle {\left(\frac{1}{50}\right)}^{-1}=}$${\displaystyle 50}$.