453 Вправа 453Алгебра 8 клас Бевз 2025 · § 9 · стор. 91

453. Обчисли значення виразу.

а) ${\displaystyle {\left(\frac{3}{2}\right)}^2-4^{-1}\cdot 5=}$${\displaystyle \frac{9}{4}-\frac{5}{4}=}$${\displaystyle 1}$;

б) ${\displaystyle -{\left(\frac{2}{3}\right)}^{-4}+0,25^2\cdot 11^2}$=

=${\displaystyle -{\left(\frac{3}{2}\right)}^4+{(0,25\cdot 11)}^2=}$${\displaystyle -\frac{81}{16}+\frac{121}{16}=}$${\displaystyle \frac{40}{16}=}$${\displaystyle 2,5}$;

в) ${\displaystyle 2\frac{1}{2}\cdot {\left(\frac{2}{5}\right)}^{-2}+35\cdot 2^{-3}=}$${\displaystyle \frac{5}{2}\cdot \frac{25}{4}+\frac{35}{8}}$=

=${\displaystyle \frac{125+35}{8}=}$${\displaystyle 20}$;

г) ${\displaystyle 0,6^{-3}:1\frac{2}{3}-{\left(\frac{3}{4}\right)}^{-2}=}$${\displaystyle {\left(\frac{5}{3}\right)}^3:\frac{5}{3}-{\left(\frac{4}{3}\right)}^2}$=

=${\displaystyle {\left(\frac{5}{3}\right)}^2-\frac{16}{9}=}$${\displaystyle \frac{25-16}{9}=}$${\displaystyle 1}$.