377° Вправа 377Алгебра 8 клас Тарасенкова 2025 · § 10 · стор. 106

377. Запишіть як степінь з натуральним показником:

${\displaystyle A^{-1}=}$${\displaystyle \frac{1}{A}}$; ${\displaystyle {\left(\frac{A}{B}\right)}^{-1}=}$${\displaystyle \frac{B}{A}}$.

1) ${\displaystyle {(b+9)}^{-1}=}$${\displaystyle \frac{1}{b+9}}$;

2) ${\displaystyle {(x-y)}^{-1}=}$${\displaystyle \frac{1}{x-y}}$;

3) ${\displaystyle {(a^3-b^3)}^{-1}=}$${\displaystyle \frac{1}{a^3-b^3}}$;

4) ${\displaystyle {\left(\frac{1}{x-y}\right)}^{-1}=}$${\displaystyle x-y}$;

5) ${\displaystyle {\left(\frac{1}{2mp}\right)}^{-1}=}$${\displaystyle 2mp}$;

6) ${\displaystyle {\left(\frac{1}{z^2-x^2}\right)}^{-1}=}$${\displaystyle z^2-x^2}$;

7) ${\displaystyle {\left(\frac{x-1}{x+3}\right)}^{-1}=}$${\displaystyle \frac{x+3}{x-1}}$;

8) ${\displaystyle {\left(\frac{x}{z+y}\right)}^{-1}=}$${\displaystyle \frac{z+y}{x}}$;

9) ${\displaystyle {\left(\frac{2a-b}{b+3a}\right)}^{-1}=}$${\displaystyle \frac{b+3a}{2a-b}}$.