187° Вправа 187Алгебра 8 клас Тарасенкова 2025 · § 5 · стор. 57

187. Спростіть вираз.

1) ${\displaystyle \frac{x}{8}\cdot \frac{x}{1}=}$${\displaystyle \frac{x^2}{8}}$;

2) ${\displaystyle \frac{5}{y}\cdot \frac{6}{1}=}$${\displaystyle \frac{30}{y}}$;

3) ${\displaystyle \frac{6a}{b^3}\cdot \frac{2b^2}{1}=}$${\displaystyle \frac{12a\cancel{b^2}}{\cancel{b^2}b}=}$${\displaystyle \frac{12a}{b}}$;

4) ${\displaystyle \frac{3}{7y}\cdot (-\frac{14y^2}{1})=}$${\displaystyle -\frac{3\cdot \stackrel{2}{\cancel{14}}\cancel{y}y}{\underset{1}{\cancel{7}}\cancel{y}}=}$${\displaystyle -6y}$;

5) ${\displaystyle \frac{6x}{15}\cdot \frac{12x^4}{1}=}$${\displaystyle \frac{\stackrel{2}{\cancel{6}}x\cdot 12x^4}{\underset{5}{\cancel{15}}}=}$${\displaystyle \frac{24x^5}{5}}$;

6) ${\displaystyle -\frac{4y^3}{1}\cdot \frac{5}{18y^4}=}$${\displaystyle -\frac{\stackrel{2}{\cancel{4}}\cancel{y^3}\cdot 5}{\underset{9}{\cancel{18}}\cancel{y^3}y}=}$${\displaystyle -\frac{10}{9y}}$.