291° Вправа 291Алгебра 8 клас Тарасенкова 2025 · § 8 · стор. 85

291. Обчисліть:

1) ${\displaystyle \frac{3}{5^{-2}}=}$${\displaystyle 3:\frac{1}{5^2}=}$${\displaystyle 3\cdot 5^2=}$${\displaystyle 3\cdot 25=}$${\displaystyle 75}$;

2) ${\displaystyle \frac{5^{-1}}{3}=}$${\displaystyle \frac{1}{5}:3=}$${\displaystyle \frac{1}{15}}$;

3) ${\displaystyle 4^0-{\left(\frac{1}{8}\right)}^{-1}=}$${\displaystyle 1-8=}$${\displaystyle -7}$;

4) ${\displaystyle {\left(7\frac{1}{8}\right)}^0+{\left(8\frac{1}{7}\right)}^0=}$${\displaystyle 1+1=}$${\displaystyle 2}$;

5) ${\displaystyle {\left(\frac{1}{3}\right)}^{-1}+{\left(\frac{1}{6}\right)}^{-1}=}$${\displaystyle 3+6=}$${\displaystyle 9}$;

6) ${\displaystyle -{\left(\frac{1}{31}\right)}^{-1}+2^5=}$${\displaystyle -31+32=}$${\displaystyle 1}$;

7) ${\displaystyle {\left(\frac{1}{10}\right)}^{-1}+{10}^{-1}+{10,01}^0=}$${\displaystyle 10+0,1+1=}$${\displaystyle 11,1}$;

8) ${\displaystyle 2^3+1^{-1}+{\left(\frac{1}{5}\right)}^{-1}=}$${\displaystyle 8+1+5=}$${\displaystyle 14}$.