304 Вправа 304Алгебра 8 клас Тарасенкова 2025 · § 8 · стор. 87

304. Обчисліть:

1) ${\displaystyle 3\cdot {\left(1\frac{1}{2}\right)}^{-2}\cdot {1,2}^{-1}=}$${\displaystyle 3\cdot {\left(\frac{3}{2}\right)}^{-2}\cdot {\left(\frac{6}{5}\right)}^{-1}=}$${\displaystyle 3\cdot {\left(\frac{2}{3}\right)}^2\cdot \frac{5}{6}=}$${\displaystyle 3\cdot \frac{4}{9}\cdot \frac{5}{6}=}$${\displaystyle \frac{\stackrel{1}{\cancel{3}}\cdot \stackrel{2}{\cancel{4}}\cdot 5}{\underset{3}{\cancel{9}}\cdot \underset{3}{\cancel{6}}}=}$${\displaystyle \frac{10}{9}=}$${\displaystyle 1\frac{1}{9}}$;

2) ${\displaystyle 5^2\cdot {0,5}^{-1}+{\left(\frac{1}{4}\right)}^{-3}\cdot {\left(\frac{2}{3}\right)}^0=}$${\displaystyle 25\cdot {\left(\frac{1}{2}\right)}^{-1}+4^3\cdot 1=}$${\displaystyle 25\cdot 2+64=}$${\displaystyle 50+64=}$${\displaystyle 114}$.