292° Вправа 292Алгебра 8 клас Тарасенкова 2025 · § 8 · стор. 85

292. Обчисліть:

1) ${\displaystyle 6^0+{12}^0=}$${\displaystyle 1+1=}$${\displaystyle 2}$;

2) ${\displaystyle {\left(5\frac{3}{4}\right)}^0+{\left(\frac{1}{4}\right)}^{-1}=}$${\displaystyle 1+4=}$${\displaystyle 5}$;

3) ${\displaystyle {\left(\frac{1}{2}\right)}^{-1}+{\left(\frac{1}{5}\right)}^{-1}=}$${\displaystyle 2+5=}$${\displaystyle 7}$;

4) ${\displaystyle -{\left(\frac{1}{14}\right)}^{-1}-{\left(\frac{1}{16}\right)}^{-1}=}$${\displaystyle -14-16=}$${\displaystyle -30}$.