232 Вправа 232Алгебра 8 клас Бевз 2025 · § 5 · стор. 51

232. Піднеси до квадрата дріб.

а) ${\displaystyle {\left(\frac{5a}{4x}\right)}^2=}$${\displaystyle \frac{{\left(5a\right)}^2}{{\left(4x\right)}^2}=}$${\displaystyle \frac{25a^2}{16x^2}}$;

б) ${\displaystyle {\left(\frac{x}{a+x}\right)}^2=}$${\displaystyle \frac{x^2}{{(a+x)}^2}=}$${\displaystyle \frac{x^2}{{\left(x+a\right)}^2}}$;

в) ${\displaystyle {\left(\frac{-m}{2a{c}^3}\right)}^2=}$${\displaystyle \frac{{(-m)}^2}{{\left(2a{c}^3\right)}^2}=}$${\displaystyle \frac{m^2}{4a^2{c}^6}}$;

г) ${\displaystyle {\left(\frac{3xz}{2a+z}\right)}^2=}$${\displaystyle \frac{{\left(3xz\right)}^2}{{(2a+z)}^2}=}$${\displaystyle \frac{9x^2{z}^2}{{\left(z+2a\right)}^2}}$.