235 Вправа 235Алгебра 8 клас Бевз 2025 · § 5 · стор. 51

235. Піднеси до степеня.

а) ${\displaystyle {\left(\frac{a-x}{a+x}\right)}^2=}$${\displaystyle \frac{{\left(a-x\right)}^2}{{\left(a+x\right)}^2}}$;

б) ${\displaystyle {\left(\frac{2a}{c-3}\right)}^5=}$${\displaystyle \frac{{\left(2a\right)}^5}{{(c-3)}^5}=}$${\displaystyle \frac{32a^5}{{\left(c-3\right)}^5}}$;

в) ${\displaystyle {\left(\frac{2ab}{3c}\right)}^2=}$${\displaystyle \frac{{\left(2ab\right)}^2}{{\left(3c\right)}^2}=}$${\displaystyle \frac{4a^2{b}^2}{9c^2}}$;

г) ${\displaystyle {\left(\frac{x^{2}z}{2a^3}\right)}^3=}$${\displaystyle \frac{{\left(x^{2}z\right)}^3}{{\left(2a^3\right)}^3}=}$${\displaystyle \frac{x^6{z}^3}{8a^9}}$.