252 Вправа 252Алгебра 8 клас Бевз 2025 · § 5 · стор. 53

252. Піднеси до степеня дріб.

а) ${\displaystyle {\left(\frac{2a^2}{3x^2{y}^3}\right)}^3=}$${\displaystyle \frac{{\left(2a^2\right)}^3}{{\left(3x^2{y}^3\right)}^3}=}$${\displaystyle \frac{8a^6}{27x^6{y}^9}}$;

б) ${\displaystyle {\left(\frac{a-c}{-2x^{2}z}\right)}^3=}$${\displaystyle \frac{{(a-c)}^3}{{(-2x^{2}z)}^3}=}$${\displaystyle \frac{{\left(a-c\right)}^3}{-8x^6{z}^3}}$;

в) ${\displaystyle {\left(\frac{3a{x}^5}{2x-1}\right)}^2=}$${\displaystyle \frac{{\left(3a{x}^5\right)}^2}{{(2x-1)}^2}=}$${\displaystyle \frac{9a^2{x}^{10}}{{\left(2x-1\right)}^2}}$.