326° Вправа 326Алгебра 8 клас Тарасенкова 2025 · § 9 · стор. 94

326. Обчисліть:

1) ${\displaystyle \frac{2^3}{2^{-2}}=}$${\displaystyle 2^{3-\left(-2\right)}=}$${\displaystyle 2^5=}$${\displaystyle 32}$;

2) ${\displaystyle \frac{2^{-3}}{2^2}=}$${\displaystyle 2^{-3-2}=}$${\displaystyle 2^{-5}=}$${\displaystyle \frac{1}{32}}$;

3) ${\displaystyle \frac{2^3}{2^2}=}$${\displaystyle 2^{3-2}=}$${\displaystyle 2}$;

4) ${\displaystyle \frac{2^{-3}}{2^{-2}}=}$${\displaystyle 2^{-3-\left(-2\right)}=}$${\displaystyle 2^{-1}=}$${\displaystyle \frac{1}{2}}$;

5) ${\displaystyle \frac{2^{-2}}{2^{-2}}=}$${\displaystyle 2^{-2-\left(-2\right)}=}$${\displaystyle 2^0=}$${\displaystyle 1}$.