343° Вправа 343Алгебра 8 клас Тарасенкова 2025 · § 9 · стор. 96

343. Запишіть у стандартному вигляді число:

Стандартний вигляд: ${\displaystyle a\cdot {10}^n}$, де ${\displaystyle 1\le a<10}$, ${\displaystyle n}$ — ціле.

1) ${\displaystyle 37=}$${\displaystyle 3,7\cdot {10}^1}$;

2) ${\displaystyle 19=}$${\displaystyle 1,9\cdot {10}^1}$;

3) ${\displaystyle 207=}$${\displaystyle 2,07\cdot {10}^2}$;

4) ${\displaystyle 0,02=}$${\displaystyle 2\cdot {10}^{-2}}$;

5) ${\displaystyle 0,38=}$${\displaystyle 3,8\cdot {10}^{-1}}$;

6) ${\displaystyle 13,005=}$${\displaystyle 1,3005\cdot {10}^1}$;

7) ${\displaystyle 0,065=}$${\displaystyle 6,5\cdot {10}^{-2}}$;

8) ${\displaystyle 0,000075=}$${\displaystyle 7,5\cdot {10}^{-5}}$;

9) ${\displaystyle 91\cdot {10}^3=}$${\displaystyle 9,1\cdot {10}^1\cdot {10}^3=}$${\displaystyle 9,1\cdot {10}^4}$;

10) ${\displaystyle 482\cdot {10}^{-5}=}$${\displaystyle 4,82\cdot {10}^2\cdot {10}^{-5}=}$${\displaystyle 4,82\cdot {10}^{-3}}$;

11) ${\displaystyle 11500\cdot {10}^3=}$${\displaystyle 1,15\cdot {10}^4\cdot {10}^3=}$${\displaystyle 1,15\cdot {10}^7}$;

12) ${\displaystyle 43000\cdot {10}^{-3}=}$${\displaystyle 4,3\cdot {10}^4\cdot {10}^{-3}=}$${\displaystyle 4,3\cdot {10}^1}$;

13) ${\displaystyle 0,00027\cdot {10}^{-2}=}$${\displaystyle 2,7\cdot {10}^{-4}\cdot {10}^{-2}=}$${\displaystyle 2,7\cdot {10}^{-6}}$;

14) ${\displaystyle 0,00011\cdot {10}^3=}$${\displaystyle 1,1\cdot {10}^{-4}\cdot {10}^3=}$${\displaystyle 1,1\cdot {10}^{-1}}$;

15) ${\displaystyle 0,305\cdot {10}^{-2}=}$${\displaystyle 3,05\cdot {10}^{-1}\cdot {10}^{-2}=}$${\displaystyle 3,05\cdot {10}^{-3}}$.