32 Вправа 32Алгебра 8 клас Бевз 2025 · § 1 · стор. 11

а) ${\displaystyle \frac{3x-12}{4}=}$${\displaystyle -3}$

${\displaystyle 3x-12=}$${\displaystyle -12}$;

${\displaystyle 3x=}$${\displaystyle 0}$;

${\displaystyle x=}$${\displaystyle 0}$;

б) ${\displaystyle \frac{3x-12}{4}=}$${\displaystyle 0}$

${\displaystyle 3x-12=}$${\displaystyle 0}$;

${\displaystyle 3x=}$${\displaystyle 12}$;

${\displaystyle x=}$${\displaystyle 4}$;

в) ${\displaystyle \frac{3x-12}{4}=}$${\displaystyle 1}$

${\displaystyle 3x-12=}$${\displaystyle 4}$;

${\displaystyle 3x=}$${\displaystyle 16}$;

${\displaystyle x=}$${\displaystyle \frac{16}{3}}$;

${\displaystyle x=}$${\displaystyle 5\frac{1}{3}}$;

г) ${\displaystyle \frac{3x-12}{4}=}$${\displaystyle 3}$

${\displaystyle 3x-12=}$${\displaystyle 12}$;

${\displaystyle 3x=}$${\displaystyle 24}$;

${\displaystyle x=}$${\displaystyle 8}$.