628 Вправа 628Алгебра 8 клас Бевз 2025 · § 13 · стор. 126

628. Заповни таблицю.

${\displaystyle \sqrt{0}=}$${\displaystyle 0}$, бо ${\displaystyle 0^2=}$${\displaystyle 0}$;

${\displaystyle \sqrt{0,01}=}$${\displaystyle 0,1}$, бо ${\displaystyle 0,1^2=}$${\displaystyle 0,01}$;

${\displaystyle \sqrt{0,04}=}$${\displaystyle 0,2}$, бо ${\displaystyle 0,2^2=}$${\displaystyle 0,04}$;

${\displaystyle \sqrt{0,09}=}$${\displaystyle 0,3}$, бо ${\displaystyle 0,3^2=}$${\displaystyle 0,09}$;

${\displaystyle \sqrt{0,16}=}$${\displaystyle 0,4}$, бо ${\displaystyle 0,4^2=}$${\displaystyle 0,16}$;

${\displaystyle \sqrt{0,25}=}$${\displaystyle 0,5}$, бо ${\displaystyle 0,5^2=}$${\displaystyle 0,25}$;

${\displaystyle \sqrt{0,36}=}$${\displaystyle 0,6}$, бо ${\displaystyle 0,6^2=}$${\displaystyle 0,36}$;

${\displaystyle \sqrt{0,49}=}$${\displaystyle 0,7}$, бо ${\displaystyle 0,7^2=}$${\displaystyle 0,49}$;

${\displaystyle \sqrt{0,64}=}$${\displaystyle 0,8}$, бо ${\displaystyle 0,8^2=}$${\displaystyle 0,64}$;

${\displaystyle \sqrt{0,81}=}$${\displaystyle 0,9}$, бо ${\displaystyle 0,9^2=}$${\displaystyle 0,81}$;

${\displaystyle \sqrt{1}=}$${\displaystyle 1}$, бо ${\displaystyle 1^2=}$${\displaystyle 1}$.