652 Вправа 652Алгебра 8 клас Бевз 2025 · § 13 · стор. 128

652. Обчисли.

а) ${\displaystyle \sqrt{\frac{121}{64}}=}$${\displaystyle \frac{11}{8}}$, бо ${\displaystyle {\left(\frac{11}{8}\right)}^2=}$${\displaystyle \frac{121}{64}}$;

${\displaystyle \frac{11}{8}=}$${\displaystyle 1\frac{3}{8}}$;

б) ${\displaystyle \sqrt{\frac{225}{81}}=}$${\displaystyle \frac{15}{9}}$, бо ${\displaystyle {\left(\frac{15}{9}\right)}^2=}$${\displaystyle \frac{225}{81}}$;

${\displaystyle \frac{15}{9}=}$${\displaystyle \frac{5}{3}=}$${\displaystyle 1\frac{2}{3}}$;

в) ${\displaystyle \sqrt{1\frac{7}{9}}=}$${\displaystyle \sqrt{\frac{16}{9}}=}$${\displaystyle \frac{4}{3}=}$${\displaystyle 1\frac{1}{3}}$;

г) ${\displaystyle \sqrt{6\frac{1}{4}}=}$${\displaystyle \sqrt{\frac{25}{4}}=}$${\displaystyle \frac{5}{2}=}$${\displaystyle 2\frac{1}{2}}$;

ґ) ${\displaystyle \sqrt{0,0025}=}$${\displaystyle 0,05}$, бо ${\displaystyle 0,05^2=}$${\displaystyle 0,0025}$;

д) ${\displaystyle \sqrt{0,0081}=}$${\displaystyle 0,09}$, бо ${\displaystyle 0,09^2=}$${\displaystyle 0,0081}$;

е) ${\displaystyle \sqrt{10,89}=}$${\displaystyle 3,3}$, бо ${\displaystyle 3,3^2=}$${\displaystyle 10,89}$;

є) ${\displaystyle \sqrt{12,25}=}$${\displaystyle 3,5}$, бо ${\displaystyle 3,5^2=}$${\displaystyle 12,25}$.

Мішане число спершу записуємо неправильним дробом: ${\displaystyle 1\frac{7}{9}=}$${\displaystyle \frac{9+7}{9}=}$${\displaystyle \frac{16}{9}}$.