667 Вправа 667Алгебра 8 клас Бевз 2025 · § 13 · стор. 129

667. Розв’яжи рівняння.

Якщо ${\displaystyle \sqrt{x}=}$${\displaystyle m}$ і ${\displaystyle m\ge 0}$, то ${\displaystyle x=}$${\displaystyle m^2}$.

а) ${\displaystyle \sqrt{x}=}$${\displaystyle 7}$;

${\displaystyle x=}$${\displaystyle 7^2}$;

${\displaystyle x=}$${\displaystyle 49}$;

б) ${\displaystyle 3-\sqrt{x}=}$${\displaystyle 0}$;

${\displaystyle \sqrt{x}=}$${\displaystyle 3}$;

${\displaystyle x=}$${\displaystyle 3^2}$;

${\displaystyle x=}$${\displaystyle 9}$;

в) ${\displaystyle 2\cdot \sqrt{x}=}$${\displaystyle 12}$;

${\displaystyle \sqrt{x}=}$${\displaystyle 12:2}$;

${\displaystyle \sqrt{x}=}$${\displaystyle 6}$;

${\displaystyle x=}$${\displaystyle 6^2}$;

${\displaystyle x=}$${\displaystyle 36}$.