653 Вправа 653Алгебра 8 клас Бевз 2025 · § 13 · стор. 128

653. Обчисли.

а) ${\displaystyle \sqrt{11\frac{1}{9}}=}$${\displaystyle \sqrt{\frac{100}{9}}=}$${\displaystyle \frac{10}{3}=}$${\displaystyle 3\frac{1}{3}}$;

б) ${\displaystyle \sqrt{6\frac{1}{4}}=}$${\displaystyle \sqrt{\frac{25}{4}}=}$${\displaystyle \frac{5}{2}=}$${\displaystyle 2\frac{1}{2}}$;

в) ${\displaystyle \sqrt{6\frac{19}{25}}=}$${\displaystyle \sqrt{\frac{169}{25}}=}$${\displaystyle \frac{13}{5}=}$${\displaystyle 2\frac{3}{5}}$;

г) ${\displaystyle \sqrt{5\frac{1}{16}}=}$${\displaystyle \sqrt{\frac{81}{16}}=}$${\displaystyle \frac{9}{4}=}$${\displaystyle 2\frac{1}{4}}$;

ґ) ${\displaystyle \sqrt{0,0001}=}$${\displaystyle 0,01}$, бо ${\displaystyle 0,01^2=}$${\displaystyle 0,0001}$;

д) ${\displaystyle \sqrt{0,0169}=}$${\displaystyle 0,13}$, бо ${\displaystyle 0,13^2=}$${\displaystyle 0,0169}$;

е) ${\displaystyle \sqrt{10,24}=}$${\displaystyle 3,2}$, бо ${\displaystyle 3,2^2=}$${\displaystyle 10,24}$;

є) ${\displaystyle \sqrt{98,01}=}$${\displaystyle 9,9}$, бо ${\displaystyle 9,9^2=}$${\displaystyle 98,01}$.