101° Вправа 101Алгебра 8 клас Тарасенкова 2025 · § 2 · стор. 32

101. Скоротіть дріб.

1) ${\displaystyle \frac{4b^3}{b^2-b^4}=}$${\displaystyle \frac{\cancel{b^2}\cdot 4b}{\cancel{b^2}(1-b^2)}=}$${\displaystyle \frac{4b}{1-b^2}}$;

2) ${\displaystyle \frac{9c^3-6c^2}{12c^2}=}$${\displaystyle \frac{\cancel{3c^2}(3c-2)}{\cancel{3c^2}\cdot 4}=}$${\displaystyle \frac{3c-2}{4}}$;

3) ${\displaystyle \frac{8x^4-8x^2}{2x^3-2x}=}$${\displaystyle \frac{8x^2(x^2-1)}{2x(x^2-1)}=}$${\displaystyle \frac{4x\cancel{2x}\cancel{\left(x^2-1\right)}}{\cancel{2x}\cancel{\left(x^2-1\right)}}=}$${\displaystyle 4x}$;

4) ${\displaystyle \frac{4y^2-12y^3}{3y^3-y^2}=}$${\displaystyle \frac{4y^2(1-3y)}{y^2(3y-1)}=}$${\displaystyle \frac{4\cancel{y^2}\cancel{\left(1-3y\right)}}{-\cancel{y^2}\cancel{\left(1-3y\right)}}=}$${\displaystyle -4}$.