98° Вправа 98Алгебра 8 клас Тарасенкова 2025 · § 2 · стор. 31

98. Скоротіть дріб.

1) ${\displaystyle \frac{6x-24y}{4x}=}$${\displaystyle \frac{\stackrel{1}{\cancel{2}}(3x-12y)}{\underset{2}{\cancel{4}}x}=}$${\displaystyle \frac{3x-12y}{2x}}$;

2) ${\displaystyle \frac{ac+bc}{3c}=}$${\displaystyle \frac{\cancel{c}(a+b)}{\cancel{c}\cdot 3}=}$${\displaystyle \frac{a+b}{3}}$;

3) ${\displaystyle \frac{bx-by}{2bc}=}$${\displaystyle \frac{\cancel{b}(x-y)}{\cancel{b}\cdot 2c}=}$${\displaystyle \frac{x-y}{2c}}$;

4) ${\displaystyle \frac{6y-6z}{y-z}=}$${\displaystyle \frac{6\cancel{\left(y-z\right)}}{\cancel{y-z}}=}$${\displaystyle 6}$;

5) ${\displaystyle \frac{11x+22y}{2ay+ax}=}$${\displaystyle \frac{11\cancel{\left(x+2y\right)}}{a\cancel{\left(x+2y\right)}}=}$${\displaystyle \frac{11}{a}}$;

6) ${\displaystyle \frac{5x-25y}{15y-3x}=}$${\displaystyle \frac{5(x-5y)}{3(5y-x)}=}$${\displaystyle \frac{5\cancel{\left(x-5y\right)}}{-3\cancel{\left(x-5y\right)}}=}$${\displaystyle -\frac{5}{3}}$.