627° Вправа 627Алгебра 8 клас Тарасенкова 2025 · § 15 · стор. 188

627. Спростіть вираз:

1) ${\displaystyle {\left(\sqrt{x-3}\right)}^2=}$${\displaystyle x-3}$;

2) ${\displaystyle {\left(\sqrt{x+9}\right)}^2=}$${\displaystyle x+9}$;

3) ${\displaystyle {\left(\sqrt{2x-7}\right)}^2=}$${\displaystyle 2x-7}$;

4) ${\displaystyle {\left(\sqrt{x^2-4}\right)}^2=}$${\displaystyle x^2-4}$;

5) ${\displaystyle {\left(\sqrt{\frac{5}{x-5}}\right)}^2=}$${\displaystyle \frac{5}{x-5}}$;

6) ${\displaystyle {\left(\sqrt{\frac{x+4}{x-16}}\right)}^2=}$${\displaystyle \frac{x+4}{x-16}}$.