519° Вправа 519Алгебра 8 клас Тарасенкова 2025 · § 13 · стор. 156

519. Обчисліть:

1) ${\displaystyle \sqrt{\frac{1}{4}}=}$${\displaystyle \frac{\sqrt{1}}{\sqrt{4}}=}$${\displaystyle \frac{1}{2}}$;

2) ${\displaystyle \sqrt{\frac{1}{16}}=}$${\displaystyle \frac{\sqrt{1}}{\sqrt{16}}=}$${\displaystyle \frac{1}{4}}$;

3) ${\displaystyle \sqrt{\frac{16}{25}}=}$${\displaystyle \frac{\sqrt{16}}{\sqrt{25}}=}$${\displaystyle \frac{4}{5}}$;

4) ${\displaystyle \sqrt{\frac{9}{100}}=}$${\displaystyle \frac{\sqrt{9}}{\sqrt{100}}=}$${\displaystyle \frac{3}{10}=}$${\displaystyle 0,3}$;

5) ${\displaystyle \sqrt{\frac{49}{64}}=}$${\displaystyle \frac{\sqrt{49}}{\sqrt{64}}=}$${\displaystyle \frac{7}{8}}$;

6) ${\displaystyle \sqrt{\frac{49}{100}}=}$${\displaystyle \frac{\sqrt{49}}{\sqrt{100}}=}$${\displaystyle \frac{7}{10}=}$${\displaystyle 0,7}$;

7) ${\displaystyle \sqrt{\frac{9}{16}}=}$${\displaystyle \frac{\sqrt{9}}{\sqrt{16}}=}$${\displaystyle \frac{3}{4}}$;

8) ${\displaystyle \sqrt{\frac{49}{81}}=}$${\displaystyle \frac{\sqrt{49}}{\sqrt{81}}=}$${\displaystyle \frac{7}{9}}$.