555 Вправа 555Алгебра 8 клас Тарасенкова 2025 · § 13 · стор. 161

555. Обчисліть:

1) ${\displaystyle {\left(3\sqrt{2}\right)}^2=}$${\displaystyle 3^2\cdot {\left(\sqrt{2}\right)}^2=}$${\displaystyle 9\cdot 2=}$${\displaystyle 18}$;

2) ${\displaystyle {\left(2\sqrt{3}\right)}^2=}$${\displaystyle 2^2\cdot {\left(\sqrt{3}\right)}^2=}$${\displaystyle 4\cdot 3=}$${\displaystyle 12}$;

3) ${\displaystyle {(-5\sqrt{5})}^2=}$${\displaystyle 5^2\cdot {\left(\sqrt{5}\right)}^2=}$${\displaystyle 25\cdot 5=}$${\displaystyle 125}$;

4) ${\displaystyle {\left(2\sqrt{2}\right)}^2=}$${\displaystyle 2^2\cdot {\left(\sqrt{2}\right)}^2=}$${\displaystyle 4\cdot 2=}$${\displaystyle 8}$;

5) ${\displaystyle {(-3\sqrt{5})}^2=}$${\displaystyle 3^2\cdot {\left(\sqrt{5}\right)}^2=}$${\displaystyle 9\cdot 5=}$${\displaystyle 45}$;

6) ${\displaystyle {\left(2\sqrt{0,4}\right)}^2=}$${\displaystyle 2^2\cdot {\left(\sqrt{0,4}\right)}^2=}$${\displaystyle 4\cdot 0,4=}$${\displaystyle 1,6}$;

7) ${\displaystyle {(-\frac{\sqrt{3}}{2})}^2=}$${\displaystyle \frac{{\left(\sqrt{3}\right)}^2}{2^2}=}$${\displaystyle \frac{3}{4}}$;

8) ${\displaystyle {\left(\frac{1}{\sqrt{2}}\right)}^2=}$${\displaystyle \frac{1}{{\left(\sqrt{2}\right)}^2}=}$${\displaystyle \frac{1}{2}}$.