528° Вправа 528Алгебра 8 клас Тарасенкова 2025 · § 13 · стор. 157

528. Обчисліть:

1) ${\displaystyle \sqrt{36\cdot 1}=}$${\displaystyle \sqrt{36}\cdot \sqrt{1}=}$${\displaystyle 6\cdot 1=}$${\displaystyle 6}$;

2) ${\displaystyle \sqrt{9\cdot 4}=}$${\displaystyle \sqrt{9}\cdot \sqrt{4}=}$${\displaystyle 3\cdot 2=}$${\displaystyle 6}$;

3) ${\displaystyle \sqrt{25\cdot 4}=}$${\displaystyle \sqrt{25}\cdot \sqrt{4}=}$${\displaystyle 5\cdot 2=}$${\displaystyle 10}$;

4) ${\displaystyle \sqrt{81\cdot 4}=}$${\displaystyle \sqrt{81}\cdot \sqrt{4}=}$${\displaystyle 9\cdot 2=}$${\displaystyle 18}$;

5) ${\displaystyle \sqrt{81\cdot 9}=}$${\displaystyle \sqrt{81}\cdot \sqrt{9}=}$${\displaystyle 9\cdot 3=}$${\displaystyle 27}$;

6) ${\displaystyle \sqrt{100\cdot 16\cdot 9}=}$${\displaystyle \sqrt{100}\cdot \sqrt{16}\cdot \sqrt{9}=}$${\displaystyle 10\cdot 4\cdot 3=}$${\displaystyle 120}$;

7) ${\displaystyle \sqrt{4\cdot 100\cdot 100}=}$${\displaystyle \sqrt{4}\cdot \sqrt{100}\cdot \sqrt{100}=}$${\displaystyle 2\cdot 10\cdot 10=}$${\displaystyle 200}$;

8) ${\displaystyle \sqrt{64\cdot 25\cdot 4}=}$${\displaystyle \sqrt{64}\cdot \sqrt{25}\cdot \sqrt{4}=}$${\displaystyle 8\cdot 5\cdot 2=}$${\displaystyle 80}$;

9) ${\displaystyle \sqrt{16\cdot 49\cdot 25}=}$${\displaystyle \sqrt{16}\cdot \sqrt{49}\cdot \sqrt{25}=}$${\displaystyle 4\cdot 7\cdot 5=}$${\displaystyle 140}$;

10) ${\displaystyle \sqrt{64\cdot 16\cdot 100}=}$${\displaystyle \sqrt{64}\cdot \sqrt{16}\cdot \sqrt{100}=}$${\displaystyle 8\cdot 4\cdot 10=}$${\displaystyle 320}$.