556 Вправа 556Алгебра 8 клас Тарасенкова 2025 · § 13 · стор. 161

556. Обчисліть:

1) ${\displaystyle {\left(5\sqrt{3}\right)}^2=}$${\displaystyle 5^2\cdot {\left(\sqrt{3}\right)}^2=}$${\displaystyle 25\cdot 3=}$${\displaystyle 75}$;

2) ${\displaystyle {(-10\sqrt{7})}^2=}$${\displaystyle {10}^2\cdot {\left(\sqrt{7}\right)}^2=}$${\displaystyle 100\cdot 7=}$${\displaystyle 700}$;

3) ${\displaystyle {\left(2\sqrt{0,5}\right)}^2=}$${\displaystyle 2^2\cdot {\left(\sqrt{0,5}\right)}^2=}$${\displaystyle 4\cdot 0,5=}$${\displaystyle 2}$;

4) ${\displaystyle {(-\frac{\sqrt{11}}{5})}^2=}$${\displaystyle \frac{{\left(\sqrt{11}\right)}^2}{5^2}=}$${\displaystyle \frac{11}{25}}$.