527° Вправа 527Алгебра 8 клас Тарасенкова 2025 · § 13 · стор. 157

527. Обчисліть:

1) ${\displaystyle {\left(\sqrt{2}\right)}^2=}$${\displaystyle 2}$;

2) ${\displaystyle {(-\sqrt{2})}^2=}$${\displaystyle {\left(\sqrt{2}\right)}^2=}$${\displaystyle 2}$;

3) ${\displaystyle {\left(\sqrt{0}\right)}^2=}$${\displaystyle 0}$;

4) ${\displaystyle {\left(\sqrt{0,7}\right)}^2=}$${\displaystyle 0,7}$;

5) ${\displaystyle {(-\sqrt{5,7})}^2=}$${\displaystyle {\left(\sqrt{5,7}\right)}^2=}$${\displaystyle 5,7}$;

6) ${\displaystyle {\left(\sqrt{\frac{1}{7}}\right)}^2=}$${\displaystyle \frac{1}{7}}$.