523° Вправа 523Алгебра 8 клас Тарасенкова 2025 · § 13 · стор. 156

523. Порівняйте числа:

1) ${\displaystyle \sqrt{5}>0}$;

2) ${\displaystyle 0>-\sqrt{15}}$;

3) ${\displaystyle \sqrt{100}=}$${\displaystyle 10}$; ${\displaystyle 10>-10}$; ${\displaystyle \sqrt{100}>-10}$;

4) ${\displaystyle -4<0<\sqrt{2}}$; ${\displaystyle -4<\sqrt{2}}$;

5) ${\displaystyle \sqrt{21}>0>-\sqrt{7}}$; ${\displaystyle \sqrt{21}>-\sqrt{7}}$;

6) ${\displaystyle 9>0>-\sqrt{90}}$; ${\displaystyle 9>-\sqrt{90}}$;

7) ${\displaystyle 4=}$${\displaystyle \sqrt{16}}$; ${\displaystyle 17>16}$; ${\displaystyle \sqrt{17}>4}$;

8) ${\displaystyle 3=}$${\displaystyle \sqrt{9}}$; ${\displaystyle 9>8}$; ${\displaystyle 3>\sqrt{8}}$;

9) ${\displaystyle 10=}$${\displaystyle \sqrt{100}}$; ${\displaystyle 99<100}$; ${\displaystyle \sqrt{99}<10}$;

10) ${\displaystyle 8=}$${\displaystyle \sqrt{64}}$; ${\displaystyle 62<64}$; ${\displaystyle \sqrt{62}<8}$;

11) ${\displaystyle 6=}$${\displaystyle \sqrt{36}}$; ${\displaystyle 36<39}$; ${\displaystyle 6<\sqrt{39}}$;

12) ${\displaystyle 4=}$${\displaystyle \sqrt{16}}$; ${\displaystyle 12<16}$; ${\displaystyle \sqrt{12}<4}$.