526° Вправа 526Алгебра 8 клас Тарасенкова 2025 · § 13 · стор. 157

526. Обчисліть:

1) ${\displaystyle {\left(\sqrt{4}\right)}^2=}$${\displaystyle 4}$;

2) ${\displaystyle {\left(\sqrt{3}\right)}^2=}$${\displaystyle 3}$;

3) ${\displaystyle {(-\sqrt{3})}^2=}$${\displaystyle {\left(\sqrt{3}\right)}^2=}$${\displaystyle 3}$;

4) ${\displaystyle {\left(\sqrt{9}\right)}^2=}$${\displaystyle 9}$;

5) ${\displaystyle {(-\sqrt{10})}^2=}$${\displaystyle {\left(\sqrt{10}\right)}^2=}$${\displaystyle 10}$;

6) ${\displaystyle {\left(\sqrt{0,2}\right)}^2=}$${\displaystyle 0,2}$;

7) ${\displaystyle {\left(\sqrt{0,99}\right)}^2=}$${\displaystyle 0,99}$;

8) ${\displaystyle {\left(\sqrt{1,1}\right)}^2=}$${\displaystyle 1,1}$;

9) ${\displaystyle {\left(\sqrt{\frac{2}{5}}\right)}^2=}$${\displaystyle \frac{2}{5}}$;

10) ${\displaystyle {\left(\sqrt{\frac{1}{8}}\right)}^2=}$${\displaystyle \frac{1}{8}}$;

11) ${\displaystyle {\left(\sqrt{\frac{21}{50}}\right)}^2=}$${\displaystyle \frac{21}{50}}$;

12) ${\displaystyle {\left(\sqrt{\frac{33}{34}}\right)}^2=}$${\displaystyle \frac{33}{34}}$.