541° Вправа 541Алгебра 8 клас Тарасенкова 2025 · § 13 · стор. 159

541. Спростіть вираз:

1) ${\displaystyle \sqrt{2}+\sqrt{2}=}$${\displaystyle (1+1)\sqrt{2}=}$${\displaystyle 2\sqrt{2}}$;

2) ${\displaystyle 7\sqrt{3}-\sqrt{3}=}$${\displaystyle (7-1)\sqrt{3}=}$${\displaystyle 6\sqrt{3}}$;

3) ${\displaystyle 6\sqrt{5}+2\sqrt{5}-3\sqrt{5}=}$${\displaystyle (6+2-3)\sqrt{5}=}$${\displaystyle 5\sqrt{5}}$;

4) ${\displaystyle 9\sqrt{11}-2\sqrt{11}=}$${\displaystyle (9-2)\sqrt{11}=}$${\displaystyle 7\sqrt{11}}$;

5) ${\displaystyle 3\sqrt{21}-4\sqrt{21}=}$${\displaystyle (3-4)\sqrt{21}=}$${\displaystyle -\sqrt{21}}$;

6) ${\displaystyle 8\sqrt{15}+2\sqrt{15}-10\sqrt{15}=}$${\displaystyle (8+2-10)\sqrt{15}=}$${\displaystyle 0}$;

7) ${\displaystyle 4\sqrt{7}-3\sqrt{7}+\sqrt{7}=}$${\displaystyle (4-3+1)\sqrt{7}=}$${\displaystyle 2\sqrt{7}}$;

8) ${\displaystyle 10\sqrt{10}+5\sqrt{10}-2\sqrt{10}=}$${\displaystyle (10+5-2)\sqrt{10}=}$${\displaystyle 13\sqrt{10}}$.