530° Вправа 530Алгебра 8 клас Тарасенкова 2025 · § 13 · стор. 157

530. Знайдіть значення виразу:

1) ${\displaystyle \sqrt{2}\cdot \sqrt{2}=}$${\displaystyle {\left(\sqrt{2}\right)}^2=}$${\displaystyle 2}$;

2) ${\displaystyle \sqrt{20}\cdot \sqrt{20}=}$${\displaystyle {\left(\sqrt{20}\right)}^2=}$${\displaystyle 20}$;

3) ${\displaystyle \sqrt{0,5}\cdot \sqrt{0,5}=}$${\displaystyle {\left(\sqrt{0,5}\right)}^2=}$${\displaystyle 0,5}$;

4) ${\displaystyle \sqrt{2}\cdot \sqrt{8}=}$${\displaystyle \sqrt{2\cdot 8}=}$${\displaystyle \sqrt{16}=}$${\displaystyle 4}$;

5) ${\displaystyle \sqrt{3}\cdot \sqrt{27}=}$${\displaystyle \sqrt{3\cdot 27}=}$${\displaystyle \sqrt{81}=}$${\displaystyle 9}$;

6) ${\displaystyle \sqrt{0,05}\cdot \sqrt{45}=}$${\displaystyle \sqrt{0,05\cdot 45}=}$${\displaystyle \sqrt{2,25}=}$${\displaystyle 1,5}$;

7) ${\displaystyle \sqrt{5}\cdot \sqrt{10}\cdot \sqrt{2}=}$${\displaystyle \sqrt{5\cdot 10\cdot 2}=}$${\displaystyle \sqrt{100}=}$${\displaystyle 10}$;

8) ${\displaystyle \sqrt{7}\cdot \sqrt{14}\cdot \sqrt{8}=}$${\displaystyle \sqrt{7\cdot 7\cdot 2\cdot 2\cdot 4}=}$${\displaystyle \sqrt{7^2\cdot 2^2\cdot 2^2}=}$${\displaystyle 7\cdot 2\cdot 2=}$${\displaystyle 28}$;

9) ${\displaystyle \sqrt{80}\cdot \sqrt{10}\cdot \sqrt{0,02}=}$${\displaystyle \sqrt{80\cdot 10\cdot 0,02}=}$${\displaystyle \sqrt{16}=}$${\displaystyle 4}$.