542° Вправа 542Алгебра 8 клас Тарасенкова 2025 · § 13 · стор. 159

542. Спростіть вираз:

1) ${\displaystyle \sqrt{10}+\sqrt{10}=}$${\displaystyle (1+1)\sqrt{10}=}$${\displaystyle 2\sqrt{10}}$;

2) ${\displaystyle -\sqrt{7}+\sqrt{7}=}$${\displaystyle 0}$;

3) ${\displaystyle 10\sqrt{23}-20\sqrt{23}-30\sqrt{23}=}$${\displaystyle (10-20-30)\sqrt{23}=}$${\displaystyle -40\sqrt{23}}$;

4) ${\displaystyle 8\sqrt{2}-\sqrt{2}-4\sqrt{2}+5\sqrt{2}=}$${\displaystyle (8-1-4+5)\sqrt{2}=}$${\displaystyle 8\sqrt{2}}$.