360 Вправа 360Алгебра 8 клас Бевз 2025 · § 7 · стор. 71

360. Обчисли.

а) ${\displaystyle (\frac{1}{2}-\frac{1}{8}):(-2)-16\frac{1}{4}:(-4)}$;

1) ${\displaystyle \frac{1}{2}-\frac{1}{8}=}$${\displaystyle \frac{4-1}{8}=}$${\displaystyle \frac{3}{8}}$;

2) ${\displaystyle \frac{3}{8}:(-2)=}$${\displaystyle -\frac{3}{16}}$;

3) ${\displaystyle 16\frac{1}{4}:(-4)=}$${\displaystyle -\frac{65}{4}\cdot \frac{1}{4}=}$${\displaystyle -\frac{65}{16}}$;

4) ${\displaystyle -\frac{3}{16}-(-\frac{65}{16})=}$${\displaystyle \frac{62}{16}=}$${\displaystyle \frac{31}{8}=}$${\displaystyle 3\frac{7}{8}}$;

б) ${\displaystyle (-\frac{1}{2}-\frac{3}{4}):(-3)+\frac{1}{3}-(-\frac{1}{6}):(-2)}$;

1) ${\displaystyle -\frac{1}{2}-\frac{3}{4}=}$${\displaystyle -\frac{2+3}{4}=}$${\displaystyle -\frac{5}{4}}$;

2) ${\displaystyle -\frac{5}{4}:(-3)=}$${\displaystyle \frac{5}{12}}$;

3) ${\displaystyle -\frac{1}{6}:(-2)=}$${\displaystyle \frac{1}{12}}$;

4) ${\displaystyle \frac{5}{12}+\frac{1}{3}-\frac{1}{12}=}$${\displaystyle \frac{5+4-1}{12}=}$${\displaystyle \frac{8}{12}=}$${\displaystyle \frac{2}{3}}$.