48 Вправа 48Алгебра 8 клас Бевз 2025 · § 2 · стор. 18

На що

Скорочення

${\displaystyle a}$

${\displaystyle \frac{a^3}{a^5}=}$${\displaystyle \frac{a^2\cdot \cancel{a}}{a^4\cdot \cancel{a}}=}$${\displaystyle \frac{a^2}{a^4}}$;

${\displaystyle a^2}$

${\displaystyle \frac{a^3}{a^5}=}$${\displaystyle \frac{a\cdot \cancel{a^2}}{a^3\cdot \cancel{a^2}}=}$${\displaystyle \frac{a}{a^3}}$;

${\displaystyle a^3}$

${\displaystyle \frac{a^3}{a^5}=}$${\displaystyle \frac{1\cdot \cancel{a^3}}{a^2\cdot \cancel{a^3}}=}$${\displaystyle \frac{1}{a^2}}$;

На що

Скорочення

${\displaystyle x}$

${\displaystyle \frac{8x^5}{12x^4}=}$${\displaystyle \frac{8x^4\cdot \cancel{x}}{12x^3\cdot \cancel{x}}=}$${\displaystyle \frac{8x^4}{12x^3}}$;

${\displaystyle x^2}$

${\displaystyle \frac{8x^5}{12x^4}=}$${\displaystyle \frac{8x^3\cdot \cancel{x^2}}{12x^2\cdot \cancel{x^2}}=}$${\displaystyle \frac{8x^3}{12x^2}}$;

${\displaystyle x^3}$

${\displaystyle \frac{8x^5}{12x^4}=}$${\displaystyle \frac{8x^2\cdot \cancel{x^3}}{12x\cdot \cancel{x^3}}=}$${\displaystyle \frac{8x^2}{12x}}$;

${\displaystyle x^4}$

${\displaystyle \frac{8x^5}{12x^4}=}$${\displaystyle \frac{8x\cdot \cancel{x^4}}{12\cdot \cancel{x^4}}=}$${\displaystyle \frac{8x}{12}}$;

${\displaystyle 4x}$

${\displaystyle \frac{8x^5}{12x^4}=}$${\displaystyle \frac{2x^4\cdot \cancel{4x}}{3x^3\cdot \cancel{4x}}=}$${\displaystyle \frac{2x^4}{3x^3}}$;

${\displaystyle 2x^2}$

${\displaystyle \frac{8x^5}{12x^4}=}$${\displaystyle \frac{4x^3\cdot \cancel{2x^2}}{6x^2\cdot \cancel{2x^2}}=}$${\displaystyle \frac{4x^3}{6x^2}}$;

${\displaystyle 4x^4}$

${\displaystyle \frac{8x^5}{12x^4}=}$${\displaystyle \frac{2x\cdot \cancel{4x^4}}{3\cdot \cancel{4x^4}}=}$${\displaystyle \frac{2x}{3}}$;