65° Вправа 65Алгебра 8 клас Тарасенкова 2025 · § 1 · стор. 20

65. Знайдіть значення виразів за таблицею 3.

Заповнена таблиця:

Обчислення.

1) ${\displaystyle c=}$${\displaystyle -1}$, ${\displaystyle d=}$${\displaystyle 1}$:

${\displaystyle (-1+1):(-1-1)=}$${\displaystyle 0:(-2)=}$${\displaystyle 0}$;

${\displaystyle \frac{-1-3\cdot 1}{1+1}=}$${\displaystyle \frac{-4}{2}=}$${\displaystyle -2}$;

2) ${\displaystyle c=}$${\displaystyle 9}$, ${\displaystyle d=}$${\displaystyle 2}$:

${\displaystyle (9+2):(9-2)=}$${\displaystyle 11:7=}$${\displaystyle \frac{11}{7}=}$${\displaystyle 1\frac{4}{7}}$;

${\displaystyle \frac{9-3\cdot 2}{1+2}=}$${\displaystyle \frac{3}{3}=}$${\displaystyle 1}$;

3) ${\displaystyle c=}$${\displaystyle -3}$, ${\displaystyle d=}$${\displaystyle 2\frac{2}{3}}$:

${\displaystyle (-3+2\frac{2}{3}):(-3-2\frac{2}{3})=}$${\displaystyle (-\frac{1}{3}):(-5\frac{2}{3})=}$${\displaystyle \frac{1}{3}:\frac{17}{3}=}$${\displaystyle \frac{1}{\underset{1}{\cancel{3}}}\cdot \frac{\stackrel{1}{\cancel{3}}}{17}=}$${\displaystyle \frac{1}{17}}$;

${\displaystyle \frac{-3-3\cdot 2\frac{2}{3}}{1+2\frac{2}{3}}=}$${\displaystyle \frac{-3-8}{3\frac{2}{3}}=}$${\displaystyle -11:\frac{11}{3}=}$${\displaystyle -\cancel{11}\cdot \frac{3}{\underset{1}{\cancel{11}}}=}$${\displaystyle -3}$;

4) ${\displaystyle c=}$${\displaystyle -3}$, ${\displaystyle d=}$${\displaystyle 0,2}$:

${\displaystyle (-3+0,2):(-3-0,2)=}$${\displaystyle -2,8:(-3,2)=}$${\displaystyle \frac{28}{32}=}$${\displaystyle \frac{7}{8}}$;

${\displaystyle \frac{-3-3\cdot 0,2}{1+0,2}=}$${\displaystyle \frac{-3,6}{1,2}=}$${\displaystyle -3}$.