736 Вправа 736Алгебра 8 клас Бевз 2025 · § 15 · стор. 143

736. Обчисли значення добутку.

а) ${\displaystyle \sqrt{50}\cdot \sqrt{8}=}$${\displaystyle \sqrt{400}=}$${\displaystyle 20}$;

б) ${\displaystyle \sqrt{3}\cdot \sqrt{12}=}$${\displaystyle \sqrt{36}=}$${\displaystyle 6}$;

в) ${\displaystyle \sqrt{2}\cdot \sqrt{242}=}$${\displaystyle \sqrt{484}=}$${\displaystyle 22}$;

г) ${\displaystyle \sqrt{11}\cdot \sqrt{99}=}$${\displaystyle \sqrt{11\cdot 11\cdot 9}=}$${\displaystyle 11\cdot 3=}$${\displaystyle 33}$;

ґ) ${\displaystyle \sqrt{37}\cdot \sqrt{3700}=}$${\displaystyle \sqrt{37\cdot 37\cdot 100}}$=

=${\displaystyle 37\cdot 10=}$${\displaystyle 370}$;

д) ${\displaystyle \sqrt{444}\cdot \sqrt{111}=}$${\displaystyle \sqrt{4\cdot 111\cdot 111}}$=

=${\displaystyle 2\cdot 111=}$${\displaystyle 222}$;

е) ${\displaystyle \sqrt{1,2}\cdot \sqrt{120}=}$${\displaystyle \sqrt{144}=}$${\displaystyle 12}$;

є) ${\displaystyle \sqrt{40}\cdot \sqrt{62,5}=}$${\displaystyle \sqrt{2500}=}$${\displaystyle 50}$;

ж) ${\displaystyle \sqrt{0,72}\cdot \sqrt{0,98}=}$${\displaystyle \sqrt{0,36\cdot 2\cdot 0,49\cdot 2}}$=

=${\displaystyle \sqrt{0,36\cdot 0,49\cdot 4}=}$${\displaystyle 0,6\cdot 0,7\cdot 2=}$${\displaystyle 0,84}$.