738 Вправа 738Алгебра 8 клас Бевз 2025 · § 15 · стор. 144

738. Обчисли значення добутку.

а) ${\displaystyle \sqrt{1\frac{4}{9}}\cdot \sqrt{1\frac{3}{13}}=}$${\displaystyle \sqrt{\frac{13}{9}\cdot \frac{16}{13}}=}$${\displaystyle \sqrt{\frac{\cancel{13}\cdot 16}{9\cdot \cancel{13}}}=}$${\displaystyle \sqrt{\frac{16}{9}}}$=

=${\displaystyle \frac{4}{3}=}$${\displaystyle 1\frac{1}{3}}$;

б) ${\displaystyle \sqrt{3\frac{1}{3}}\cdot \sqrt{1\frac{1}{5}}=}$${\displaystyle \sqrt{\frac{10}{3}\cdot \frac{6}{5}}=}$${\displaystyle \sqrt{\frac{2\cdot \cancel{5}\cdot 2\cdot \cancel{3}}{\cancel{3}\cdot \cancel{5}}}=}$${\displaystyle \sqrt{4}=}$${\displaystyle 2}$;

в) ${\displaystyle \sqrt{3\frac{1}{2}}\cdot \sqrt{\frac{8}{7}}=}$${\displaystyle \sqrt{\frac{7}{2}\cdot \frac{8}{7}}=}$${\displaystyle \sqrt{\frac{\cancel{7}\cdot 4\cdot \cancel{2}}{\cancel{2}\cdot \cancel{7}}}=}$${\displaystyle \sqrt{4}=}$${\displaystyle 2}$.