2 Вправа 2Алгебра 8 клас Тарасенкова 2025 · Розділ 1 · стор. 5

2. Знайдіть значення виразу.

1) ${\displaystyle -3^2+4^3-5^4+{10}^2=}$${\displaystyle -9+64-625+100=}$${\displaystyle -470}$;

2) ${\displaystyle -2^9-{(-2)}^8+2^7=}$${\displaystyle -2^9-2^8+2^7=}$${\displaystyle 2^7\cdot (-2^2-2+1)=}$${\displaystyle 2^7\cdot (-4-2+1)=}$${\displaystyle 128\cdot (-5)=}$${\displaystyle -640}$;

3) ${\displaystyle {0,4}^2\cdot {\left(\frac{5}{2}\right)}^3+{1,2}^4\cdot {\left(1\frac{2}{3}\right)}^4=}$${\displaystyle {\left(\frac{2}{5}\right)}^2\cdot {\left(\frac{5}{2}\right)}^2\cdot \frac{5}{2}+{\left(\frac{6}{5}\right)}^4\cdot {\left(\frac{5}{3}\right)}^4=}$${\displaystyle {(\frac{\stackrel{1}{\cancel{2}}}{\underset{1}{\cancel{5}}}\cdot \frac{\stackrel{1}{\cancel{5}}}{\underset{1}{\cancel{2}}})}^2\cdot \frac{5}{2}+{(\frac{2\cdot \stackrel{1}{\cancel{3}}}{\underset{1}{\cancel{5}}}\cdot \frac{\stackrel{1}{\cancel{5}}}{\underset{1}{\cancel{3}}})}^4=}$${\displaystyle 1^2\cdot \frac{5}{2}+2^4=}$${\displaystyle 2,5+16=}$${\displaystyle 18,5}$;

4) ${\displaystyle (-{20}^4:{\left({(-4)}^2\right)}^2):5^2=}$${\displaystyle (-{20}^4:4^4):5^2=}$${\displaystyle -{(20:4)}^4:5^2=}$${\displaystyle -5^4:5^2=}$${\displaystyle -5^2=}$${\displaystyle -25}$.