901 Вправа 901Алгебра 8 клас Бевз 2025 · § 18 · стор. 173

901. Розв’яжи рівняння.

а) ${\displaystyle 2x^2-8x=}$${\displaystyle 0}$;

${\displaystyle 2x(x-4)=}$${\displaystyle 0}$;

${\displaystyle x_1=}$${\displaystyle 0,x_2=}$${\displaystyle 4}$;

б) ${\displaystyle x^2+3x=}$${\displaystyle 0}$;

${\displaystyle x(x+3)=}$${\displaystyle 0}$;

${\displaystyle x_1=}$${\displaystyle 0,x_2=}$${\displaystyle -3}$;

в) ${\displaystyle 12x=}$${\displaystyle 0,24x^2}$;

${\displaystyle 0,24x^2-12x=}$${\displaystyle 0}$;

${\displaystyle 0,24x(x-50)=}$${\displaystyle 0}$;

${\displaystyle x_1=}$${\displaystyle 0,x_2=}$${\displaystyle 50}$;

г) ${\displaystyle x-x^2=}$${\displaystyle 0}$;

${\displaystyle x(1-x)=}$${\displaystyle 0}$;

${\displaystyle x_1=}$${\displaystyle 0,x_2=}$${\displaystyle 1}$;

ґ) ${\displaystyle -0,1x^2=}$${\displaystyle 0}$;

${\displaystyle x^2=}$${\displaystyle 0}$;

${\displaystyle x=}$${\displaystyle 0}$;

д) ${\displaystyle 9x^2=}$${\displaystyle 0}$;

${\displaystyle x^2=}$${\displaystyle 0}$;

${\displaystyle x=}$${\displaystyle 0}$;

е) ${\displaystyle 9x^2=}$${\displaystyle 64}$;

${\displaystyle x^2=}$${\displaystyle \frac{64}{9}}$;

${\displaystyle x=}$${\displaystyle \pm \frac{8}{3}=}$${\displaystyle \pm 2\frac{2}{3}}$;

є) ${\displaystyle -2x^2+50=}$${\displaystyle 0}$;

${\displaystyle 2x^2=}$${\displaystyle 50}$;

${\displaystyle x^2=}$${\displaystyle 25}$;

${\displaystyle x=}$${\displaystyle \pm 5}$;

ж) ${\displaystyle 100x^2-225=}$${\displaystyle 0}$;

${\displaystyle 100x^2=}$${\displaystyle 225}$;

${\displaystyle x^2=}$${\displaystyle 2,25}$;

${\displaystyle x=}$${\displaystyle \pm 1,5}$.