790 Вправа 790Алгебра 8 клас Бевз 2025 · § 16 · стор. 152

790. Внеси множник під знак кореня.

а) ${\displaystyle \frac{1}{2}\sqrt{\frac{2}{3}}=}$${\displaystyle \sqrt{\frac{1}{4}\cdot \frac{2}{3}}=}$${\displaystyle \sqrt{\frac{2}{12}}=}$${\displaystyle \sqrt{\frac{1}{6}}}$;

б) ${\displaystyle -3\sqrt{\frac{2}{3}}=}$${\displaystyle -\sqrt{9\cdot \frac{2}{3}}=}$${\displaystyle -\sqrt{6}}$;

в) ${\displaystyle 1\frac{1}{2}\sqrt{\frac{2}{33}}=}$${\displaystyle \sqrt{\frac{9}{4}\cdot \frac{2}{33}}=}$${\displaystyle \sqrt{\frac{18}{132}}=}$${\displaystyle \sqrt{\frac{3}{22}}}$;

г) ${\displaystyle -2\frac{1}{4}\sqrt{5\frac{1}{3}}=}$${\displaystyle -\sqrt{\frac{81}{16}\cdot \frac{16}{3}}=}$${\displaystyle -\sqrt{\frac{81}{3}}=}$${\displaystyle -\sqrt{27}}$.