791 Вправа 791Алгебра 8 клас Бевз 2025 · § 16 · стор. 152

791. Внеси множник під знак кореня.

а) ${\displaystyle \frac{1}{2}\sqrt{2}=}$${\displaystyle \sqrt{\frac{1}{4}\cdot 2}=}$${\displaystyle \sqrt{\frac{1}{2}}}$;

б) ${\displaystyle -\frac{2}{3}\sqrt{\frac{3}{2}}=}$${\displaystyle -\sqrt{\frac{4}{9}\cdot \frac{3}{2}}=}$${\displaystyle -\sqrt{\frac{2}{3}}}$;

в) ${\displaystyle 1\frac{1}{5}\sqrt{2\frac{1}{2}}=}$${\displaystyle \sqrt{\frac{36}{25}\cdot \frac{5}{2}}=}$${\displaystyle \sqrt{\frac{18}{5}}=}$${\displaystyle \sqrt{3,6}}$;

г) ${\displaystyle -3\frac{2}{5}\sqrt{\frac{5}{17}}=}$${\displaystyle -\sqrt{\frac{289}{25}\cdot \frac{5}{17}}=}$${\displaystyle -\sqrt{\frac{17}{5}}=}$${\displaystyle -\sqrt{3,4}}$.