802 Вправа 802Алгебра 8 клас Бевз 2025 · § 16 · стор. 153

802. Виконай дії.

а) ${\displaystyle (2-\sqrt{3})(4+2\sqrt{3})=}$${\displaystyle 8+4\sqrt{3}-4\sqrt{3}-6=}$${\displaystyle 2}$;

б) ${\displaystyle (6-3\sqrt{2})(2-\sqrt{2})}$=

=${\displaystyle 12-6\sqrt{2}-6\sqrt{2}+6=}$${\displaystyle 18-12\sqrt{2}}$;

в) ${\displaystyle (2\sqrt{3}+1)(2\sqrt{3}-1)=}$${\displaystyle {\left(2\sqrt{3}\right)}^2-1}$=

=${\displaystyle 12-1=}$${\displaystyle 11}$;

г) ${\displaystyle (4+3\sqrt{7})(3\sqrt{7}-4)=}$${\displaystyle {\left(3\sqrt{7}\right)}^2-4^2}$=

=${\displaystyle 63-16=}$${\displaystyle 47}$.